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Php Mysql Ajax Add Edit Delete In Php: Implementing Datatables Features with Ajax, PHP and MySQL



After successful CRUD action, the AJAX callback will update the status on the browser. Let us learn how to add, edit and delete records in the MySQL database using PHP via AJAX. If you are looking for a non-AJAX plain PHP CRUD, go through my previous tutorial.




Php Mysql Ajax Add Edit Delete In Php



In this tutorial, I will explain how to insert, view, edit and delete record from database using PHP and Mysqli, basically this tutorial is a second part of Simple User Registration & Login Script in PHP and MySQLi, in this first part I explained how to create simple user registration and login using PHP and MySQLi, if you do not know how to create user registration and user login form so kindly first check this tutorial Simple User Registration & Login Script in PHP and MySQLi, after that now come back to this tutorial.


Now I am assuming that you have already created user registration and login forms which I created in Simple User Registration & Login Script in PHP and MySQLi now I will create another table to keeping records in it, update dashboard.php file and add four more new pages which are insert.php, view.php, edit.php, and delete.php, follow the following steps:


I downloaded the tutorial and ran it and it works as planned! However, when I switch to another table I can get data to display and can delete a record but when I try to edit a field it does not work. I have checked that the fields have same text-encoding, unsigned, type, length etc, but still cannot get it to work. I have also checked variable and field names for error and there are none. Any help would be appreciated.


Hi Sanjeet, I have already shared how to insert, edit, view and delete in very simple way using PHP. I would suggest, first download my tutorial and try to execute the same file. If it is working then understand how the codes are working through my tutorial explanation then try to edit code as per your need. Hope this will help you to edit.


I can retrieve records, I can go to insert, but it will not insert records, errors out. I cannot edit records, errors out. I can delete records no problem. Can I email you my code to look at? My database is for internal network, no external access.


what does the $con stands for? what does it define ,it is found on the edit page and $result = mysqli_query($con,$sel_query); while($row = mysqli_fetch_assoc($result)) { ?> what does the above code fine?


So now we know how to display records from our MySQL database, take note that the buttons that appear in the table (create, edit, and delete) will not work, that's because we haven't created those pages yet.


This post is the extended version of my previous article post i.e. How to insert data using jQuery Ajax in PHP. In the previous article we have seen how to do insert using jquery ajax methods with php but we have not covered select, update and delete. So to cover every under one umbrella we have developed this step by step tutorial to show you how to do insert, update, delete and select using jQuery Ajax in addition with jQuery Animation Effects with PHP.


In this step create a new php file and name it as "index.php" and in the same file write a html code to create a employer input form to take the input data from the employee and save it in the database. This form should be in the "div" box with div id "#mforminsert". We have created this "div" with div id "#mforminsert" box because we will use this div box to load the form using the ajax methods while editing records.


Once the data inserted to the mysql database it will return last inserted data value (employee_id it returns back to jQuery.ajax success callback function). If the data inserted successfully jQuery creates a new element i.e. <span> tag with span id as record followed by last data inserted ID (This value returns from mysql database i.e. employee_id) by using jQuery.appendTo() method.


On edit anchor link and delete anchor link onClick() event we have called new javascript function called ActionFunction(urls, empids, work) with three input values i.e.


The process of this function is same as we did it while adding new record. Same way first form will be validated and post all data to "updatedb_file.php" using $.ajax method. Once the mysql data is updated successfully then only that span element is get refreshed or loaded with updated data.


Below is the javascript function which is used to delete a single record from the mysql database. Once the data is deleted from database the associated span id element is also get removed from "index.php" file.


So hey friends this is all about select, insert, update and delete using jQuery $.ajax animation effects with php scripting code. Please Note while loading data, inserting data to mysql, updating data to mysql or deleting data everything is done by using jQuery animation effects that is using jQuery.fadeIn(), jQuery.slideUp(), jQuery.slideDown(), jQuery.fadeOut() methods.


So, The First thing you need to include below mentioned code inside the index.php page, the below code helps us to display the Modal, once the modal has appeared, then we will be able to get the Table record inside the Modal. Update Form Update Now Close You need to paste the code inside the index.php page, once you add that, then you need to include the below-mentioned jQuery Code. The jQuery Code helps us to display the Modal and also get a particular record inside the Modal.//Get Particular Recordfunction get_record() $(document).on('click','#btn_edit',function() var ID = $(this).attr('data-id'); $.ajax( url: 'get_data.php', method: 'post', data:UserID:ID, dataType: 'JSON', success: function(data) $('#Up_User_ID').val(data[0]); $('#Up_UserName').val(data[1]); $('#Up_UserEmail').val(data[2]); $('#update').modal('show'); ) )Finally, you need to use Php to get the particular record inside Modal, So, you need to use the below-mentioned code. That helps us to display the particular record inside Modal. // Get Particular Record function get_record() global $con; $UserID = $_POST['UserID']; $query = "select * from user_record where ID='$UserID'"; $result = mysqli_query($con,$query); while($row=mysqli_fetch_assoc($result)) $User_data = ""; $User_data[0]=$row['ID']; $User_data[1]=$row['UserName']; $User_data[2]=$row['UserEmail']; echo json_encode($User_data); Once you display the particular record inside the Modal, then you will be able to perform the operation namely Update the Record. So, the First thing you need to get the value from the Modal Inside the Modal has input text fields, you need to use the below-mentioned jQuery code to get the record and send Ajax request in Php Page.


In this tutorial, you will learn how to delete data in PHP & MySQL using ajax we know that this is a common function when creating software. So I hope that you will learn from this simple method and use it in your future project.


With the help of ajax we are enabled to request the server to delete a specific record without reloading our page and automatically remove our record in the lists. So for you to understand we use a Simple Employee Database to delete a record.


I have a editable data table having the following code. Now i have a json data which has all the data for the fields. I am new to jquery and dont know and have been struggling to input the data from json to this code. Please help me out. I would be very much thankful. Need help with a simple code explaining how to do the editable data table save, edit, delete and update


When Multiple Images uploaded into the folder then after we have to insert uploaded images details like image name and description in the table. So every uploaded image data will be inserted into the Mysql table. After uploading the image we have by using Ajax function fetch image details from the Mysql table and display on the web page in table format with edit and delete button.


As developers, we're always asked to do more for our users. They want their Web pages faster, smaller, and with more features. This means that you have to start working more in JavaScript and jQuery on the client-side. By doing more client-side coding, you reduce post-backs to the server, thereby increasing performance. In this first article of a series on working within HTML and the Web API, I'll show you how to add, edit, and delete data in an HTML table using JavaScript and jQuery, but no post-backs. In subsequent articles, you'll learn how to take that data and use the Web API to retrieve and modify this data.


To demonstrate the concepts for this article, I created a page called Paul's Training Videos (Figure 1). This page allows me to list all of my training videos on Pluralsight, and eventually, to add, edit, and delete them. I'm using Bootstrap in order to have a nice appearance for my Web page, but it's not required.


You've learned how to add and delete rows from an HTML table. Now, turn your attention to editing rows in an HTML table. Just like you added a Delete button to each row in your table, add an Edit button as well (Figure 4). Once more, you need to modify the element by adding a new element with the word Edit, as shown in the following code snippet.


Data from database is fetched and displayed in index.php file. This is our homepage. This file also contains a link to add data. On every row of displayed data, there is also a link to edit and delete data. Below is a sample image of our homepage:


Inline data editing provides an easy way to edit data in table cells without loading another component. If your web application has data grid functionality, inline edit & delete is the must-have feature. The user can edit and delete content on the same page by clicking the row in the table. Inline table data editing provides a better user experience and makes the web application user-friendly. 2ff7e9595c


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